FTIR Data
I need assistance completing this lab report along with it's Pre-Lab Questions. I've attached all the documents with the relevant information
Sample Name Sample Form Operator Name Resolution Scantime or Scans Sample Scans Start Frequency Limit for File End Frequency Limit for File
c2d2 c2d2 Student 0.49
16 4000 400
Aperture Setting Beamsplitter Setting Detector Setting Source Setting Measurement Channel Acquisition Mode Phase Correction Mode Apodization Function
6 mm KBr RT-DLaTGS [Internal] MIR Sample Compartment Double Sided,Forward-Backward Mertz Blackman-Harris 3-Term
100010101020103010401050106010701080
Wavenumber cm-1
0. 0
0. 1
0. 2
0. 3
0. 4
0. 5
0. 6
0. 7
A bs
or ba
nc e
U ni
ts
Page 1/2
Wavenumber 1096.9006 1093.3347 1091.5616 1089.7369 1087.8910 1086.0302 1084.2185 1082.3311 1080.5535 1078.6560 1076.9358 1075.0403 1073.3231 1071.4155 1069.6914 1067.8003 1066.0516 1064.2019 1062.4643 1060.6337 1058.9051 1057.1088 1055.3734 1053.5948 1051.8647 1050.0822 1048.3382 1046.6176 1044.8969 1043.2135 1041.3480 1039.8244 1038.1092 1036.3572 1034.7268 1033.0087 1031.3891 1029.6929 1028.0638 1026.3868 1024.7916 1023.1437 1021.5476
Abs. intensity 0.012 0.045 0.027 0.121 0.071 0.165 0.111 0.240 0.172 0.329 0.251 0.420 0.344 0.518 0.420 0.583 0.451 0.624 0.470 0.649 0.516 0.646 0.559 0.648 0.536 0.546 0.408 0.421 0.252 0.209 0.191 0.091 0.221 0.313 0.344 0.321 0.492 0.425 0.569 0.502 0.620 0.547 0.621
Rel. intensity 0.060 0.084 0.055 0.131 0.078 0.165 0.098 0.215 0.136 0.282 0.197 0.359 0.279 0.423 0.316 0.469 0.312 0.526 0.343 0.741 0.405 0.547 0.446 0.557 0.450 0.479 0.360 0.390 0.233 0.208 0.188 0.110 0.241 0.309 0.346 0.299 0.455 0.368 0.495 0.408 0.515 0.417 0.656
Width 1.1361 0.8113 0.5777 0.6789 0.5592 0.7604 0.6264 0.7454 0.7464 0.8102 0.8877 0.8556 0.8108 0.8098 0.7070 0.7241 0.6665 0.7530 0.7526 0.9882 0.7572 0.7241 0.7000 0.6952 0.6742 0.6755 0.6809 0.7028 0.6874 0.7134 0.7020 0.6814 0.6999 0.6834 0.6984 0.6693 0.6892 0.6790 0.6782 0.6731 0.6889 0.6744 0.9364
Found if threshold < 6.597848 10.513943 7.581129 18.416073 10.394702 23.153616 12.677317 30.124146 17.896210 39.524586 27.139685 50.327503 38.969521 59.287010 43.776245 65.742287 40.895084 73.823669 44.304535 101.443916 54.709381 75.652489 62.491005 78.049149 62.084766 66.476974 49.158283 54.050823 31.906317 28.477516 24.544422 14.443577 32.758224 42.093277 47.963371 39.805222 63.079975 50.217793 68.710014 56.008827 71.575470 56.623192 91.530518
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FTIR Lab Report Guidelines Ravi Ranjan
CHEM 343 Fall 2018
I. Title Page a. Set title to center of page horizontally and vertically b. Experiment title should be larger font than author info (it must be obvious that it
is the title) c. Author info includes: Name, Partner Name, Date, TA d. Title page should not have a number, report pages are numbered
II. Abstract a. Short paragraph summarizing report (most journals have a 300-word limit, you
will not be held to this limit) b. The objective, theoretical basis, results, and success of the experiment should be
included c. Does not need to be a separate page
III. Introduction a. Explains why the experiment is performed (since this is an educational
experiment, you will explain the theory behind it) b. Your hypothesis will be in the introduction. What do you expect the result to be?
Do you expect to see nuclear spin effects in the spectra? c. Equations should be numbered and written with the equation editor (i.e.
𝑟"# = %&',)*&',+ ,)*,+
− . / 𝑟"" should be shown instead of
rCH = sqrt((Ie,D – Ie,H)/(mD – mH)) – rCC/2) d. Any variables introduced must be defined. (i.e. The equation to determine the
area of a triangle is 𝐴 = . / 𝑏ℎ, where A is the area, b is the length of the triangle base,
and h is the triangle height perpendicular to the base) e. Use subscripts and superscripts appropriately
IV. Materials and Methods a. Contains an in-text list of items used in the experiment (i.e. CaC2, 99%; D2O, 99%; Bruker
Tensor 27 FTIR Spectrophotometer; etc.) Items separated by semicolons. descriptions separated by commas
b. A short summary of the procedure from the manual in paragraph form c. Should be detailed enough where someone else can reproduce your experiment d. Must contain explicit and implicit citation to lab manual
V. Data/Results a. No less than 2 graphs per page but must be large enough to read regression analysis b. Graphs generated in software other than MS Excel c. Graphs should be formatted with axis titles and descriptive chart title (Do not use “vs.”
in the title)
d. Data must be presented in tables with associated error values and proper significant figures
Parameter Value v (m/s) (1.23±0.02)×105 E (kJ) 1.637±0.009
e. When using scientific notation, do not use E. E-4 is different from 10-4 f. Use multiplication symbol (×) instead of asterisk (*) or letter x g. All values must have appropriate units
VI. Calculations a. Only one set of calculations needs to be shown (i.e. Show calculations for C2H2 and
report values for C2H2 & C2D2) b. Show units and conversions c. Equations should be numbered for easy reference d. Use some text between equations to explain the algebraic manipulations (i.e. like
textbooks, make it easy for me to understand your thought process) The equation for the slope of a line is given by Equation 1:
𝑦 = 𝑚𝑥 + 𝑏 (1)
From the linear regression analysis of the calibration curve, Equation 1 becomes:
𝑦 = 12.53 < = ,>?
@ × 𝑥 <,>? = @ + 0.49 (2)
The concentration of the unknown sample can be determined by solving Eq. 2 for x
𝑥 = E*F.GH
./.IJ< K LMN@
(3)
Using the absorbance of the unknown sample for y, the concentration is:
𝑥 = F.OI*F.GH
./.IJ< K LMN@
= F.JP
./.IJ< K LMN@
= 2.9 × 10*. 𝑚𝑜𝑙 𝐿⁄ (4)
e. Use MS Word equation editor or equivalent software f. Have a logical flow to the calculations, do not jump from one result to the next
VII. Discussion
a. Explain what the results mean b. Interpret the FTIR spectra (what do you see? Is it expected? Nuclear Spin effects,
Branches in the ro-vib spectrum, vibration energy difference between products, etc.) c. Connect the experiment to the theory (Demonstrate your understanding of Quantum
Mechanics as it applies to Rotational-Vibrational Spectroscopy) d. Compare the results to those from the Tidwell group (Tidwell’s findings were published
in the 1960’s) e. Comment on the differences between your experiment and Tidwell’s f. Show your confidence in your results g. If applicable, provide suggestions for improvement in the experiment (not making the
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calculation less tedious, we can’t avoid that)
VIII. Conclusion a. Simple summary of the experiment b. Results and comparison to Tidwell c. Your interpretation of the results/experiment.
,
Sample Name Sample Form Operator Name Resolution Scantime or Scans Sample Scans Start Frequency Limit for File End Frequency Limit for File
c2h2 c2h2 Student 0.49
16 4000 400
Aperture Setting Beamsplitter Setting Detector Setting Source Setting Measurement Channel Acquisition Mode Phase Correction Mode Apodization Function
6 mm KBr RT-DLaTGS [Internal] MIR Sample Compartment Double Sided,Forward-Backward Mertz Blackman-Harris 3-Term
12601280130013201340136013801400
Wavenumber cm-1
0. 0
0. 1
0. 2
0. 3
0. 4
0. 5
A bs
or ba
nc e
U ni
ts
Page 1/2
Wavenumber 1378.8598 1376.4022 1373.9185 1371.5183 1369.0193 1366.6403 1364.1856 1361.7619 1359.3495 1356.9218 1354.5353 1352.0881 1349.7152 1347.2689 1344.9032 1342.4764 1340.1217 1337.7091 1335.3362 1332.9481 1330.5465 1328.3095 1325.7863 1323.4706 1321.1317 1318.8074 1316.4675 1314.1613 1311.8308 1309.5362 1307.2229 1304.9219 1302.6397 1300.3603 1298.0770 1295.8011 1293.5503 1291.2902 1289.0600 1286.8111 1284.5743 1282.3602 1280.0985 1277.8636 1275.6028 1273.3505 1271.0665 1266.5346
Abs. intensity 0.119 0.221 0.180 0.257 0.183 0.272 0.201 0.307 0.236 0.338 0.276 0.366 0.295 0.395 0.307 0.407 0.321 0.385 0.264 0.296 0.140 0.173 0.173 0.171 0.285 0.271 0.351 0.276 0.404 0.338 0.456 0.374 0.458 0.339 0.409 0.291 0.327 0.219 0.254 0.168 0.227 0.144 0.209 0.108 0.154 0.073 0.105 0.072
Rel. intensity 0.095 0.201 0.156 0.231 0.157 0.240 0.151 0.255 0.181 0.294 0.229 0.320 0.246 0.343 0.252 0.393 0.273 0.346 0.236 0.273 0.119 0.158 0.158 0.156 0.267 0.248 0.329 0.251 0.376 0.305 0.425 0.341 0.458 0.307 0.378 0.262 0.301 0.192 0.229 0.140 0.199 0.113 0.179 0.076 0.126 0.052 0.087 0.060
Width 0.7185 0.7196 0.7581 0.7325 0.9322 0.7470 0.9024 0.7646 0.8304 0.7539 0.8113 0.7552 0.7708 0.7535 0.7332 0.8232 0.7295 0.7556 0.7105 0.7328 0.7060 0.7793 0.7113 0.7275 0.7259 0.7474 0.7411 0.7502 0.7344 0.7351 0.7200 0.7517 0.7670 0.8164 0.7435 0.9073 0.7745 1.0004 0.7724 0.9485 0.7165 0.7867 0.6838 0.7438 0.7195 0.7119 0.7511 0.7048
Found if threshold < 21.064837 44.889801 33.263550 51.563263 35.095676 53.563362 30.351547 56.830505 40.007904 65.596642 49.957428 71.525871 53.601791 76.566093 55.367092 87.701210 60.094620 75.778931 52.330627 60.697727 24.851032 35.045086 35.231693 34.572701 58.610336 55.271477 73.177155 55.518902 83.185204 67.877174 94.938370 75.933922 102.320526 68.491257 84.453056 57.920090 67.199608 42.423790 51.123993 31.070740 44.486431 25.076231 39.897247 16.737694 28.093405 10.796872 19.310709 13.392973
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R P J 1/2(R(J)-P(J)) 2J+1 1/2(R(J)-P(J+2)) 2J+3 Value Unit Value Unit Value Unit Value Unit Term Value Unit
1330.6944 0 665.3472 1 3.5364 3 299792458 ms-1 Ref. NIST Atomic mass 1.66054E-27 kg 1 amu SB0H 2.83238E-04 cm-1
1333.0724 1325.9367 1 3.56785 3 5.8964 5 6.62607E-34 Js Ref. NIST Mass of H mh 1.67349E-27 kg 1.0078 amu SB1H 4.46591E-04 cm-1
1335.4676 1323.6216 2 5.923 5 8.24935 7 -0.00303 cm-1 Mass of D md 3.34449E-27 kg 2.0141 amu SB0H^2 8.02238E-08 cm-2
1337.8087 1321.2796 3 8.26455 7 10.591 9 1.17532 cm-1 117.53 m-1 Mass of C mc 1.99447E-26 kg 12.011 amu SB1H^2 1.99444E-07 cm-2
1340.2262 1318.9689 4 10.62865 9 12.95205 11 2.38171E-46 kgm2 2.3817E-39 gcm2 1/mh 5.97553E+26 1/kg SAH 5.28836E-04 cm-1
1342.6028 1316.6267 5 12.98805 11 15.30215 13 1/md 2.98999E+26 1/kg SAH^2 2.79667E-07 cm-2
1345.0112 1314.3221 6 15.34455 13 17.65465 15 1.1751 cm-1 117.51 m-1 1/mc 5.01385E+25 1/kg SbeH 3.87480E-04 cm-1
1347.3954 1311.9985 7 17.69845 15 20.01185 17 2.38051E-46 cm-1 SbeH^2 1.50141E-07 cm-2
1349.7762 1309.7019 8 20.03715 17 22.33885 19
1352.1886 1307.3717 9 22.40845 19 SB0D 1.03358E-03 cm-1
1305.0985 10 -652.54925 1.17987 0 Inertia of C2H2 Ih 2.38171E-46 kgm2 SB1D 8.96431E-04 cm-1
0.00044659 #N/A Inertia of C2D2 Id 3.30284E-46 kgm2 SB0D^2 1.06829E-06 cm-2
1.00000 0.02 SB1D^2 8.03589E-07 cm-1
6979865 8 C-C distance rcc 1.20965E-10 m 1.20965 A SAD 1.36817E-03 cm-1
1850 0.0 C-H distance rch 1.05536E-10 m 1.05536 A SAD^2 1.87188E-06 cm-1
SbeD 1.23946E-03 cm-1
SbeD^2 1.53626E-06 cm-2
1.17684 0 Inertia of C2H2 Tih 2.38051E-46 kgm2
0.00028324 #N/A Inertia of C2D2 Tid 3.30733E-46 kgm2 dIh/dBh -2.02644E-48
1.00000 0.01032557 dId/dBd -3.89700E-48
17263499 8 C-C distance Trcc 1.20679E-10 m 1.2068 A SIH 7.85203E-52 kgm2
1841 0.00085294 C-H distance Trch 1.06191E-10 m 1.06191 A SIH^2 6.16544E-103 kg2m4
SID 4.83018E-51 kgm2
SID^2 2.33306E-101 kg2m4
R P J 1/2(R(J)-P(J)) 2J+1 1/2(R(J)-P(J+2)) 2J+3 Value Unit Value Unit C2H2 C2D2 1043.2810 0 521.6405 1 2.51045 3 299792458 ms-1 Ref. NIST Const. Unit Value Error Value Error drc/dId -4.15106E+35
1044.9781 1039.9516 1 2.51325 3 4.23955 5 6.62607E-34 Js Ref. NIST B1 cm-1 1.1799 0.0004 0.8540 0.0009 (drc/dId)^2 1.72313E+71
1046.7127 1038.2601 2 4.2263 5 5.91175 7 -0.00429 cm-1 B0 cm-1 1.1768 0.0003 0.8497 0.0010 SID^2*(drc/dId)^2 4.02016E-30
1048.4536 1036.4990 3 5.9773 7 7.6512 9 0.84754 cm-1 84.754 m-1 ae cm-1 -0.0030 0.0005 -0.0043 0.0014 drc/dIh 8.29594E+35
1050.2003 1034.8892 4 7.65555 9 9.33805 11 3.30284E-46 kgm2 3.3028E-39 gcm2 Be cm-1 1.1753 0.0004 0.8475 0.0012 (drc/dIh)^2 6.88226E+71
1051.9530 1033.1512 5 9.4009 11 11.1038 13 Ie kgm2 2.38171E-46 7.9E-52 3.30284E-46 4.8E-51 SIH^2*(drc/dIh)^2 4.24322E-31
1053.6753 1031.5242 6 11.07555 13 12.743 15 0.84604 cm-1 84.604 m-1 Ie gcm2 2.38171E-39 7.9E-45 3.30284E-39 4.8E-44
1055.4190 1029.7454 7 12.8368 15 14.49035 17 3.30639E-46 cm-1 drh/dId 9.01169E+35
1057.1915 1028.1893 8 14.5011 17 16.08965 19 rcc A 1.20965 0.00002 (drh/dId)^2 8.12106E+71
1058.9698 1026.4383 9 16.26575 19 rch A 1.05536 0.00005 SID^2*(drh/dId)^2 1.89469E-29
1025.0122 10 -512.5061 0.85397 0 drh/dIh -9.01169E+35
0.000896 #N/A (drh/dIh)^2 8.12106E+71
0.99999 0.03 SIH^2*(drh/dIh)^2 5.00699E-31
907506 8 drh/drc -5.00000E-01
969 0.01 (drh/drc)^2 2.50000E-01
SRC^2*(drh/drc)^2 1.11112E-30
0.84968 0
0.0010336 #N/A SRC 2.10819E-15 m
0.99999 0.04 SRC^2 4.44448E-30 m2
675803 8 SRH 4.53417E-15 m
959 0.01 SRH^2 2.05587E-29 m2
Spring 2020
Error Propagation
Data Summary
Table values
Calculated values
Calculation Sheet for Molecular Spectroscopy of Acetylene
B1
c=
h=
c=
Slope, m (B1)
sm
r2 of B1 curve
Const.
ae=
Be=
Ie=
Tbe=
Table values
Const.
Bond length calculation
Tie=
F
ssreg
df
Intercept of B1 Curve, b
sb
sy
sm
r2 of B0 curve
sb
sy
Slope, m (B0) Intercept of B0 Curve, b
B0
C2H2
C2D2
Tbe=
B1
sm sb
Slope, m (B1) Intercept of B1 Curve, b
Const.
ae=
Be=
Ie=
Table values
h=
r2 of B1 curve sy
Tie=
ssresid
B0
df
ssresid
F
ssreg
sy
sb
Slope, m (B0)
sm
r2 of B0 curve
Intercept of B0 Curve, b
y = 1.1799x R² = 1
0
5
10
15
20
25
0 5 10 15 20
1 /2
(R (J
)- P
(J +1
))
2J+1
B1
y = 1.1768x R² = 1
0
5
10
15
20
25
0 5 10 15 20
1 /2
(R (J
)- P
(J +2
))
2J+3
B0
y = 0.854x R² = 1
0
5
10
15
20
0 5 10 15 20
1 /2
(R (J
)- P
(J +1
))
2J+1
B1
y = 0.8497x R² = 0.9999
0
5
10
15
20
0 5 10 15 20
1 /2
(R (J
)- P
(J +2
))
2J+3
B0
Partial derivatives for error propagation
𝜎𝛼𝑒 2 = (
𝜕𝛼𝑒
𝜕𝐵0 )2𝜎𝐵0
2 + ( 𝜕𝛼𝑒
𝜕𝐵1 )2𝜎𝐵1
2
𝜎𝐵𝑒 2 = (
𝜕𝐵𝑒
𝜕𝐵0 )2𝜎𝐵0
2 + ( 𝜕𝐵𝑒
𝜕𝛼𝑒 )2𝜎𝛼𝑒
2 or 𝜎𝐵𝑒 2 = (
𝜕𝐵𝑒
𝜕𝐵1 )2𝜎𝐵1
2 + ( 𝜕𝐵𝑒
𝜕𝛼𝑒 )2𝜎𝛼𝑒
2
𝜎𝐼𝑒 2 = (
𝜕𝐼𝑒
𝜕𝐵𝑒 )2𝜎𝐵𝑒
2
𝜎𝑟𝐶𝐶 2 = (
𝜕𝑟𝐶𝐶
𝜕𝐼𝑒,𝐻 )2𝜎𝐼𝑒,𝐻
2 + ( 𝜕𝑟𝐶𝐶
𝜕𝐼𝑒,𝐷 )2𝜎𝐼𝑒,𝐷
2
𝜎𝑟𝐶𝐻 2 = (
𝜕𝑟𝐶𝐻
𝜕𝐼𝑒,𝐻 )2𝜎𝐼𝑒,𝐻
2 + ( 𝜕𝑟𝐶𝐻
𝜕𝐼𝑒,𝐷 )2𝜎𝐼𝑒,𝐷
2 + ( 𝜕𝑟𝐶𝐻
𝜕𝑟𝐶𝐶 )2𝜎𝑟𝐶𝐶
2
,
Fourier Transform Infrared Spectroscopy
A form of infrared spectroscopy that is most widely used today is Fourier
Transform infrared spectroscopy. It differs from the conventional form of spectral
acquisition by using a polychromatic source of light to irradiate the sample and
manipulating the response with a mathematical process called Fourier transformation.
One finds in an FTIR spectrometer an interferometer that makes this method of
acquisition possible. Shown in Fig. 1 is an idealized Michelson-Morley interferometer.
M1
M2
B
S
D
Fig. 1. Schematic of a basic Michelson-Morley interferometer. S = source, M1 = fixed
mirror, M2 = moving mirror, Δx = displacement, D = detector, and B = beam splitter.
The infrared light coming from the source S is directed to a beam splitter B which
allows part of the light to pass through while the rest of the light is reflected back. The
reflected part of the beam travels to the fixed mirror M1, is reflected there and hits the
beam splitter again. The same happens to the light that passed through the beam splitter.
It hits the reflecting mirror M2 . However, this mirror is moving back and forth by a
distance Δx . When the beams coming from M1 and M2 recombine at the beam splitter,
they have a difference in path length so that they interfere. The beam leaving the
interferometer goes through the sample and finally reaches the detector. The signal that
emerges from the sample is called an interferogram and is given by:
S(x) = KΦνcos(4πxν) (1)
where K = a constant that includes detector response and geometrical factors,
x = mirror displacement, Δx in Fig. 1
ν = wavenumber of the signal
Fig. 2. Detector output against mirror displacement in a Michelson-Morley
interferometer both for (a) monochromatic light and (b) a broadband source. A spectrum
from its Fourier transform is shown in (c).
Since the radiation coming from the sample is made up of polychromatic light and since
the molecule absorbs and transmits light at different frequencies, the signal is the integral
over all frequencies:
dνν)πcos(4)( –
xxS ∫ ∞
∞ νΦ= (2)
or by doing a Fourier transform, the spectrum is obtained:
xxxS dν)πcos(4)( – ∫ ∞
∞ ν =Φ (3)
This method of spectroscopy provides various advantages: (1) wavenumber
accuracy; (2) a throughput advantage so that more light reaches the sample; and (3) all
the frequencies coming from the light source hit the detector simultaneously resulting in
an acquisition of a broad range of frequencies in a single measurement.
,
4/15/2015
Molecular Spectroscopy of Acetylene
adapted by Joel Krooswyk and Michael Trenary
Published: September 23, 2013
1. Introduction
Molecular spectroscopy is one of the most powerful tools available for determining molecular structure. The very high precision with which spectroscopic transitions of gas phase molecules can be measured allows us to determine with high accuracy the bond lengths and bond angles of small molecules. In this experiment you will use a Fourier transform infrared spectrometer to measure infrared absorption spectra of normal acetylene (C2H2) and deuterium substituted acetylene (C2D2). The infrared region of the electromagnetic spectrum spans wavelength ranges of roughly λ = 2 to 25 μm (1 μm = 1 × 10-6 meter). Rather than wavelength, the related quantity, wavenumber, is often used in infrared spectroscopy. Wavenumber is simply the reciprocal of the wavelength, ν� = 1/λ, and the unit of wavenumber is cm-1. The infrared region of 2 to 25 μm is equivalent to 400 to 5000 cm-1. Other equations related to electromagnetic radiation are:
(frequency) × (wavelength) = speed of light, λν = c
Energy = (Plank’s constant) × (frequency), E = hν = hc/λ = hcν ̅
Note that both frequency and wavenumber are proportional to energy and for convenience we often use units of cm-1 to describe energies in spectroscopy, even though cm-1 is not a proper energy unit. If we need to convert a value in cm-1 units to an energy unit, such as joule, we use the above equation.
The energy of infrared radiation is sufficient to cause transitions between quantized vibrational energy levels of molecules. Hence, infrared spectroscopy is often called vibrational spectroscopy. Molecules also have quantized rotational energies that are roughly two orders of magnitude smaller than vibrational energies. When a molecule changes vibrational state, it can also change rotational state, which leads to rotational fine structure that accompanies each vibrational transition. In this experiment, you will analyze the rotational fine structure on one of the vibrational transitions that appears in the infrared spectrum of acetylene. From your analysis you will be able to determine the precise values of the C–H and C≡C bond lengths of acetylene.
2. Theoretical background
The peaks that you will measure are due to transitions between different energy levels in the acetylene molecule. Hence, to predict the wavenumber position of a peak, you need to know the initial and final state energies of the molecule. These states are specified by a vibrational
1
4/15/2015
quantum number, υ, and a rotational quantum number, J. If we use cm-1 units for the energy levels, then the position of a line in our spectrum is given by
ν� = E f(υ f ,J f ) – E i(υ i ,J i ) (1)
where i and f refer to the initial and final states, respectively. We start by using a Born- Oppenheimer separation of the vibrational and rotational energies and treat them as independent so that the total energy is the sum of the two. This is an approximation, but correct for the inaccuracies due to this approximation by adding a small correction term.
The vibrational energies are based on the harmonic oscillator approximation, which gives a series of evenly spaced levels given by
E(υ) = hν(υ+½), where υ = 0, 1, 2, 3, 4, 5, … (2)
and where the separation between any two adjacent levels is given by
E(υ+1) – E(υ) = hν . (3)
The selection rule for harmonic oscillators are such that in an absorption spectrum (as opposed to an emission spectrum) only transitions for which the υ quantum number increases by 1, i.e., Δυ = +1, are allowed. This would correspond to a peak in the IR absorption spectrum at hν , in proper energy units, or at E/hc in wavenumber units. As presented below, most molecules are in their ground vibrational state at room temperature and so the infrared absorption spectrum consists of only υ = 0 → υ = 1 transitions, which are known as vibrational fundamentals. For a diatomic molecule, the stretching of the bond corresponds to the displacement in the harmonic oscillator model. For a polyatomic molecule, there are multiple bonds that can be stretched as well as bond angles that can bend as the molecule vibrates. If we make what is called the harmonic approximation, then there are only a certain number of distinct ways the molecule can vibrate and these ways are called normal modes. The number of normal modes for a molecule consisting of N atoms is given by one of the following two equations for the number of vibrational degrees of freedom:
3N-5, linear molecules
3N-6, non-linear molecules
Since diatomic molecules are linear, the formula correctly gives 1 normal mode for diatomics. Acetylene is also linear, so we expect 7 normal modes of acetylene. Not all of these modes are IR active. For a normal mode to be IR active, the molecule’s dipole moment has to change during the vibration. For some molecules all of the normal modes are IR active, while for others only a few of the modes are. The question of which modes are IR active depends on the symmetry of the molecule and can be addressed through the use of group theory. For acetylene, two fundamentals appear in the IR spectrum at 3281.9 and 730.3 cm-1. Besides the fundamental
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stretch and bending modes that appear in the IR spectrum, other transitions can also appear such as combination bands (two fundamental modes added together). In this experiment, you will be analyzing the combination band of the two bending (asymmetric and symmetric) modes at 1328.18 and 1041.49 cm-1 for C2H2 and C2D2, respectfully. A table showing the atomic displacement patterns of the normal modes of acetylene is shown below. Only five modes are shown because the bending modes come in degenerate pairs, i.e., there are two equivalent modes with the same frequency. The partners to the bending modes shown involve bending out of the plane of the page (as represented by the + and – signs).
Table 1. Fundamental frequencies for C2H2 for all normal modes.
The quantized rotational energy levels are based on the rigid rotor model and are given by
E(J) = BeJ(J+1) (4)
where Be is the rotational constant and J the rotational quantum number, which can be any non- negative integer, i.e., J = 0, 1, 2, 3, … . The rotational selection rule is ΔJ = ± 1. The rotational constant, in wavenumber units, is related to the masses of the atoms in the molecule and to the molecular geometry through the moment of inertia, Ie, by
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𝐵𝐵𝑒𝑒 = ℎ
8𝜋𝜋2𝑐𝑐𝐼𝐼𝑒𝑒
where the moment of inertia is defined by
𝐼𝐼𝑒𝑒 = �𝑚𝑚𝑖𝑖𝑟𝑟𝑖𝑖2 𝑁𝑁
𝑖𝑖=1
In these equations the subscript “e” refers to the equilibrium geometry. In the equation for Ie , the sum is over all the atoms in the molecule. For a linear molecule like acetylene, the ri refer to the distance of an atom from the center of mass, which for acetylene is located at the midpoint between the two carbon atoms. From analysis of the spectra, you can obtain a value for Be from which you can calculate Ie. Since you know the masses of the atoms, you can then obtain the ri and hence the bond length. Figure 1 shows a rotational energy level diagram with the ΔJ = ± 1 transitions marked by the arrows.
Figure 1. Energy diagram showing the first two transitions in the R and P branches, respectively.
To a first approximation, we can just add the energy expressions for the harmonic oscillator and rigid rotor to get E(υ,J), the vibrational rotational energy. However, this is little too drastic an approximation and we need to add a term that takes into account that vibration and rotation are not entirely independent and interact to some extent. The vibration-rotation interaction constant is αe and when it is included the energy level expression that we need can be written as
E(υ,J) = hν(υ+½) + BeJ(J+1) – αeJ(J+1)(υ+½) (7)
Note that this can be rewritten in terms of an effective rotational constant, Bυ , which is different for every vibrational level of the molecule. The idea that the effective rotational constant
(5)
(6)
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depends on vibrational level is another way of saying that vibration and rotation are not entirely independent and have some interaction. In terms of Bυ , the energy expression is then
E(υ,J) = hν(υ+½) + BυJ(J+1) (8)
where
Bυ = Be – αe(υ+½). (9)
We have neglected a couple of terms in this expression that are not important for this experiment: the anharmonicity and the centrifugal distortion. Anharmonicity accounts for deviations from an ideal harmonic oscillator, which would be important for a vibrational analysis of acetylene, and centrifugal distortion, which is mainly important for much higher values of J than we are considering. For a vibrational fundamental, υ = 0 → υ = 1, the rotational lines in the spectrum occur at lower (the P branch) wavenumber positions than the pure vibrational transition (which occurs at ν0) for ΔJ = – 1, and at higher wavenumber positions (the R branch) for the ΔJ = +1 transitions. From the above energy level expression, we can write the following two equations for the peak positions in the R and P branches of a vibrational fundamental
νR(J)= ν0 + (B0+B1)(J+1) – (B0–B1)(J+1)2 (10)
νP(J)= ν0 – (B0+B1) J – (B0–B1) J 2 (11)
These two equations will be used for the data analysis.
In addition to knowing the equations that describe the peak positions, we need to know what determines the relative intensities among the rotational transitions. The basic answer is that the intensity of a rotational line in either the P or R branch, depends on the number of molecules in the initial energy level, J, which is given by
𝑁𝑁𝐽𝐽 = 𝑔𝑔𝐽𝐽exp { −𝐸𝐸𝐽𝐽 𝑘𝑘𝑘𝑘
}
where the exponential term is the Boltzmann factor from thermodynamics. It tells us that if the energy is very high relative to the thermal energy available at an absolute temperature T (in Kelvin), then there will be relatively few molecules with that energy. If the energy is comparable to or lower than the thermal energy, then the probability will be high. Since rotational energies are small relative to kT at room temperature, there are many molecules with J values between 0 and about 30 or so. The second factor, gJ, refers to the degeneracy, which is the number of different states of the same energy. For a linear molecule, the energy depends on the quantum number J, but there is another quantum number associated with rotation, MJ , which the energy does not depend on. There are 2J+1 different MJ values for each J value, so the degeneracy associated with the different MJ values is 2J+1. (The J and MJ quantum numbers
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are exactly analgous to the angular momentum and magnetic quantum numbers in the hydrogen atom, l and m l , respectively.)
In addition to the degeneracy associated with the different M J values, symmetric molecules, such as acetylene, can have an additional degeneracy associated with what are known as nuclear spin statistics. In fact, observing the effects of nuclear spin statistics, which can have a large effect on relative intensities, is one of the main points of the acetylene IR experiment. The reason nuclear spin has anything to do with infrared spectroscopy is due to one of the most fundamental principles of quantum mechanics, the Pauli Principle. This principle states that the probability density, given by |Ψ𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡|2, must be unchanged upon the exchange of identical particles. This means that the exchange either does not change Ψ𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡, or changes it to − Ψ𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡. These two behaviors, symmetric and antisymmetric with respect to exchange, correspond to two types of particles, fermions and bosons. For fermions, the total wavefunction changes sign and is antisymmetric upon exchange, whereas for bosons the wavefunction does not change sign and is symmetric. Nuclei, such as H, that have a nuclear spin angular momentum quantum number of ½, are fermions, whereas nuclei such as D with a spin quantum number of 1, are bosons. Because of nuclear spin statistics, the relative intensities of the rotational lines in the IR absorption spectrum of C2H2 and C2D2 are qualitatively different. For the molecule C2HD, the two hydrogen atoms are not identical, so nuclear spin statistics do not affect the intensities. Although the carbon atoms are identical, 12C has a nuclear spin of zero, which means the degeneracy of the nuclear spin wavefunction is one, which in turn means there is no effect on the relative intensities.
To understand why H and D affect the relative intensities differently, we need to consider that the total wavefunction for internal motion
Ψ𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡 = ψelecψvibψrotψns
can be factored into separate electronic, vibrational, rotational, and nuclear spin wavefunctions. In general, vibrational wavefunctions are symmetric with respect to exchange of identical nuclei and so are the electronic wavefunctions of the ground states of most molecules, including acetylene. Therefore, for acetylene, the symmetry of the total wavefunction with respect to exchange depends only on the rotational and nuclear spin wavefunctions. Depending on the nuclear spin angular momentum quantum number, there can be several different nuclear spin wavefunctions, all of the same energy, so that the degeneracy of the initial state in a vibration- rotation transition depends on nuclear spin. If the nuclear spin quantum number is I, then the nuclear spin degeneracy is 2I+1 for each nucleus. (Note: quantum mechanically all angular momenta obey the same general rules; the degeneracy for the angular momentum of the hydrogen atom is 2 l+1, the degeneracy for the rotational angular momentum of the rigid rotor is 2J+1, and the degeneracy for the nuclear spin angular momentum is 2I+1). The nuclear spin degeneracy can be thought of as the number of different orientations of the nuclear spin angular momentum vector. For an I = ½ particle such as an H atom or an electron, the degeneracy is 2,
(13)
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corresponding to spin up and spin down. When equivalent nuclei are involved, such as for acetylene, then the spins of each nucleus are independent and the total nuclear spin degeneracy is (2I+1)2, i.e., this is the number of different wavefunctions possible. Of these nuclear spin wavefunctions, (2I+1)(I+1) are symmetric with respect to exchange of the equivalent nuclei and (2I+1)I are antisymmetric. So for two identical particles with I = ½, there are three symmetric spin functions and one antisymmetric function. For I = 1, there six symmetric functions, and three antisymmetric functions.
The symmetry of the rotational wavefunction with respect to exchange of identical nuclei is simply determined by the rotational quantum number. For J = even, the rotational wavefunction is symmetric with respect to exchange, while for J = odd, it is antisymmetric. To make Ψtotal antisymmetric with respect to exchange, as it must be for fermions like H, the odd J states must be combined with even nuclear spin states, and the even J states must combine with antisymmetric nuclear spin states. Therefore, the nuclear spin degeneracy for even J states for C2H2, is 1, while for odd J states it is 3. For C2D2, the even J states must combine with the symmetric nuclear spin wavefunctions, and the odd J states must combine with the antisymmetric nuclear spin states to make the overall wavefunction symmetric with respect to exchange. Therefore the nuclear spin degeneracy for the even J states of C2D2 is 6, and the degeneracy for even J values is 3. The important observable is the relative degeneracies, and this reasoning indicates that there will be a 3:1 relative intensity ratio for the rotational lines of C2H2 for initial J states of odd number relative to initial states with even Js. For C2D2, the ratio will be 2:1, with the states with even initial Js more intense. Figure 2 below shows the simulated spectra of the rotational fine structure of a linear molecule, such as acetylene, without and with the inclusion of effect of nuclear spin statistics.
Figure 2. Simulated Spectra of C2H2 without and with the inclusion of nuclear spin statistics.
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Acetylene IR Experimental Procedure
A. Reaction to produce C2H2/C2D2
For this experiment, you will be synthesizing acetylene (C2H2) and deuterated acetylene (C2D2) from calcium carbide (CaC2) and DI-water (H2O) and deuterium oxide (D2O).
CaC2 + 2 H2O –> C2H2 + Ca(OH)2
CaC2 + 2 D2O –> C2D2 + Ca(OD)2
C2H2 and C2D2 are highly flammable gases and can react with oxygen (O2), checking for leaks in the manifold is crucial before starting the synthesis.
B. Steps for safe laboratory work
Please review the following steps before starting the experiment.
1. All valves are closed on the manifold when entering and exiting the laboratory except G on both manifolds.
2. Your TA will check to make sure you are using the appropriate amounts of CaC2 and H2O/D2O. Using excess CaC2 will create a high pressure of C2H2/C2D2, which could cause an explosion in the manifold.
3. When the experiment is over, open the flask in the fume hood. This will prevent flammable/noxious gases from entering the laboratory.
4. Always wear safety goggles, you will not be allowed to perform the experiment without them. Taking them off will also result in a performance point deduction and you may possibly be asked to leave the laboratory for the day.
C. Synthesis of C2H2/C2D2 and acquiring IR spectra
1. There are two different procedures in order to synthesize C2H2 and C2D2. 2. Review and familiarize yourself with both procedures and figures in the following pages. 3. Your TA will provide liquid nitrogen to fill the dewar for the cold trap.
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To synthesize C2H2:
Figure 3. Vacuum line for sample cell preparation.
1. Fit the cold trap between the hose that leads to the mechanical pump and valve C. Make
sure valves A and B are open. Attach the spring clips across the two joints but do not
tighten them. Make sure valves are in the open position.
2. Place the empty dewar under the cold trap, raising it until it covers most of the trap.
Wrap both chains around dewar to secure it.
3. Tighten the spring clips across the joints of the trap.
4. Weigh out ~0.4 + 0.1 g of CaC2 (one or two piece(s) of CaC2) for C2H2 synthesis and put
into 500 mL flask. Do not crush CaC2.
5. Put septum on open 14/20 fitting on 500 mL flask, attach flask to manifold valve E.
6. Remove the IR cell from the dessicator.
7. Fit the inlet ball of the IR cell into the socket under valve D, and place a spring clip
across the joint. You may need to use a clamp to support the cell. The valves on the IR
cell should be closed.
Note: Do not allow the KBr windows of the IR cell to come into contact with any
moisture. Placing fingers on the window surfaces will cause damage.
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8. Open valve D, H, E, and I. Turn on mechanical pump (switch on surge protector located
on the side by the red vacuum line) and slowly open valve C. Valve C should be closed
when entering and exiting the laboratory. Fill cold trap with liquid nitrogen.
9. Wait until the pressure reaches equal or less than 0.6 Torr. If the pressure reading is not
decreasing, check to make sure the valve (valve G) to the baratron is open.
10. Check for leaks by isolating the manifold by closing valve C. Then open valve C and
close valve A. This ensures no oxygen enters the system through a leak to the
atmosphere. If pressure rises after each check, there is a leak in the manifold/cold trap.
After checking for leaks, make sure valves C and A are open.
11. Close valve E, then close H and D. Remove IR cell and acquire background spectrum on
the Bruker Tensor 27 FTIR. See instrumentation section for Bruker Tensor 27 FTIR for
instructions.
12. While taking a background scan, make an ice bath with CaCl2 and H2O. Raise bucket
around flask up to the neck (right below septum) of the flask.
13. After background scan is complete, attach IR cell back to manifold (valve H), open D,
then H. Wait for the pressure to drop in the manifold.
14. Open valve E.
15. Fill syringe with 3.0 mL H2O. Make sure there isn't any air by tapping syringe and
purging it of all bubbles. Make sure ice bath is around flask.
16. Close valves C and I. This isolates the manifold from the cold trap and pump and flask
from manifold preventing water vapor from entering the cell.
17. Inject H2O into the flask. Open valve I about 30 seconds after injection. When the
pressure starts rising in the manifold, you are synthesizing C2H2. You need 50-100 Torr
of C2H2.
18. After reaction is finished, close valve H and A. Open valve C slowly and the pressure
should drop, all remaining C2H2 in the manifold will be contained in the cold trap.
19. Open valve A after pressure has stabilized.
20. Close valve D, remove IR cell.
21. Acquire sample spectrum.
22. After acquiring spectrum, close E and I after all water vapor has been evacuated from
flask.
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23. Remove flask and put it in fume hood. Open valve I and remove septum.
24. Fill flask halfway with H2O, this will dissolve some of the Ca(OH)2 and any remaining
CaC2 will react. While filling with H2O, close fume hood window leaving just enough
space to work. Only pour the first washing of the flask into the waste labeled FTIR.
25. Use sonicator and 0.1 M HCl if Ca(OH)2 residues cannot be removed from the flask.
26. Pour rest of waste down the drain and flush with water.
27. After spectrum is acquired, remove IR cell from instrument and fit back onto manifold.
28. Open valves H and D to evacuate cell. After pressure stabilizes in manifold, close both
valves and remove from manifold.
29. Close valves C, B, and A. Turn off pump and remove cold trap. Leave cold trap in
liquid nitrogen while carrying it to the fume hood. Remove cold trap from liquid nitrogen
in hood and open valves A and B. Lower fume hood window.
To synthesize C2D2:
Figure 4. Vacuum line for sample cell preparation.
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1. Fit the cold trap between the hose that leads to the mechanical pump and valve C. Make
sure valves A and B are open. Attach the spring clips across the two joints but do not
tighten them. Make sure valves are in the open position.
2. Place the empty dewar under the cold trap, raising it until it covers most of the trap.
Wrap both chains around dewar to secure it.
3. Tighten the spring clips across the joints of the trap.
4. Weigh out ~0.8 + 0.1 g of CaC2 (one or two piece(s) of CaC2) for C2D2 synthesis and put
into 500 mL flask. Do not crush CaC2.
5. Put septum on open 14/20 fitting on 500 mL flask, attach flask to manifold valve E.
6. Attach cold finger to valve J.
7. Remove the IR cell from the dessicator.
8. Fit the inlet ball of the IR cell into the socket under valve D, and place a spring clip
across the joint. You may need to use a clamp to support the cell. The valves on the IR
cell should be closed.
Note: Do not allow the KBr windows of the IR cell to come into contact with any
moisture. Placing fingers on the window surfaces will cause damage.
9. Open valve D, H, E, I, and J. Turn on mechanical pump (switch on surge protector
located on the side by the red vacuum line) and slowly open valve C. Valve C should be
closed when entering and exiting the laboratory. Fill cold trap with liquid nitrogen.
10. Wait until the pressure reaches less than 0.6 Torr. If the pressure reading is not
decreasing, check to make sure the valve (valve G) to the baratron is open.
11. Check for leaks by isolating the manifold by closing valve C. Then open valve C and
close valve A. This ensures no oxygen enters the system through a leak to the
atmosphere. If pressure rises after each check, there is a leak in the manifold/cold trap.
After checking for leaks, make sure valves C and A are open.
12. Close valve E, then close H and D. Remove IR cell and acquire background spectrum on
the Bruker Tensor 27 FTIR. See next section for instructions.
13. While taking a background scan, fill a bucket with H2O. Raise bucket halfway up the
flask.
14. After background scan is complete, attach IR cell back to manifold (valve H), open D,
then H. Wait for the pressure to drop in the manifold.
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15. Open valve E.
16. Cool cold finger by raising the extra dewar around it and fill it with liquid nitrogen.
17. Fill syringe with 8.0 mL of D2O. Make sure there isn't any air by tapping syringe and
purging it of all bubbles. Make sure flask is submerged in the water bath.
18. Close valve C. Valve I is open in order for the D2O vapor to enter the manifold. This is to
ensure synthesis of 100% C2D2 and no partially deuterated (C2DH) or C2H2 species
formed.
19. Inject D2O into the flask. The pressure will not rise substantially due to the cold finger.
The deuterated acetylene is condensing in the cold finger due to the liquid nitrogen.
20. After the bubbles have subsided in the 500 mL flask, close valve A and open valve C.
21. Open valve A after pressure has stabilized.
22. Close valve E and I after the pressure has decreased and has stabilized (not changing).
23. Close valve C (Pressure should be less than 0.5 Torr). Lower the liquid nitrogen dewar
that is around the cold finger.
24. After the pressure rises to 200 Torr, close valves H and A.
25. Open valve C.
26. Open valve A after pressure has stabilized.
27. Close valve D, remove IR cell to acquire sample spectrum.
28. Open valves E and I to remove all D2O from flask while acquiring sample spectrum.
29. Close E and I after acquiring sample spectrum, remove flask, and put it back in fume
hood. Open valve I and remove septum.
30. Fill flask halfway with H2O, this will dissolve some of the Ca(OD)2 and any remaining
CaC2 will react. While filling with H2O, close fume hood window leaving just enough
space to work. Only pour the first washing of the flask into the waste labeled FTIR.
31. Use sonicator and 0.1 M HCl if Ca(OD)2 residues cannot be removed from the flask.
32. Pour rest of waste down the drain and flush with water.
33. After spectrum is acquired, remove IR cell from instrument and fit back onto manifold.
34. Open valves H and D to evacuate cell. After pressure stabilizes in manifold, close both
valves and remove from manifold.
35. Close valve J and remove cold finger. Rinse with H2O and place in oven. Then close
valves C, B, and A. Turn off pump and remove cold trap. Leave cold trap in liquid
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nitrogen while carrying it to the fume hood. Remove cold trap from liquid nitrogen in
hood and open valves A and B. Lower fume hood window.
Instrument Operation for the Bruker Tensor 27 FTIR
I. Loading the Software.
1. The IR software that is used for this experiment is OPUS 7.2.139.1294. To start the
program, double click on the ’OPUS 7.2.139.1294’ icon on the windows desktop. Click
login, no password is required for the program. If the screen does not appear as the same
as the print screen available on the website, click on File, Open, and click on the WORK
folder. Click on the pchem_343 file. The appearance of the program should now
resemble that of the print screen. Before any scans can be completed, the
pchem_343.xpm file must be initiated. To do this, go to the tool bar, which is located on
the top of the screen, and click on the test tube icon. Under Basic tab, make sure the
pchem_343.xpm file is loaded for the experiment (Do not click save). Change the sample
description to your names and the date, and sample form to either c2h2 or c2d2. In the
Advanced tab, go to the File Name. Put date and both of the students' names in the box.
Even though the file is saved after each spectral scan automatically, you will not have
access to it after running the experiment. Go back to Basic tab to run background scan.
II. Running a Background Scan
2. A background scan allows the user to easily subtract out the contributions of the sample
holder, solvent, instrument, and atmosphere inside the instrument from the spectra. For
every run, different solvent, or different technique of acquiring a spectrum, you must first
acquire a background spectrum. The same background, however, may be used for many
spectra. A new background should be acquired after ~60 minutes has elapsed, to account
for any change in the instrument over time.
3. To open the sample compartment, lift cover to sample compartment (light blue part of
instrument). Fit cell into the transmission holder slot. Close the sample compartment.
You want to minimize the amount of time the compartment remains open to reduce the
purge time.
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4. Wait 5 minutes after closing sample compartment to allow all of the water and carbon
dioxide (CO2) to be purged from the instrument before acquiring a scan.
5. Under the Basic tab (after clicking on the test tube icon), click on Run Background Scan.
Then click 'Accept and Exit'. NOT SAVE. Nothing will appear on the screen for the
background scan.
III. Running a Sample Scan
6. Click on test tube icon and under Basic tab click Sample Scan. The box will close
opening up a new measurement window. On the lower left hand corner of the window,
click 'Start Measurement'.
7. Once the spectrum appears on the screen, check if it is acceptable. If acceptable, you can
remove the cell from the sample holder and go to step 27 and 32 for the C2H2 and C2D2
synthetic steps, respectfully, in the experimental section.
IV. Printing Results
8. Click on the peak picking icon to the right of the test tube (it looks like three upside down
Gaussian peaks). Click on Frequency Range tab and set the limits as 1380 to 1280 for
C2H2 and 1080 to 1020 for C2D2. Then click Peak Picking. The peak number should
show up on the plot.
9. Click on the print button (located right next to the peak picking button). Make sure
layout file is acetyleneprintlayout.PLE. Go to frequency range tab. It should read for
the x startpoint and endpoint 1410 and 1250 for C2H2 and 1080 and 1000 for C2D2,
respectively. For the y minimum, it should be 0 and the y maximum is the top of
spectrum (on previous screen). This will change in regards to the pressure in the cell.
Click on Options tab. Output to printer and click print at the bottom of the box. You
should have two sheets of paper, one with the spectrum and scan settings, the other with
the peak positions in wavenumbers and their corresponding intensities. These will be
used for the data analysis.
10. Before leaving lab, close OPUS software and make sure spectrometer sample
compartment is closed.
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Spectral Analysis
I. Labeling peaks with respective J values
Figure 5. Spectrum of C2H2
Figure 6. Spectrum of C2D2
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Data Analysis
(a) Make a table of J values and the corresponding experimental frequencies from the R and P
branches. (Check out sample spectra, figs. 4 and 5 as guide, should provide frequency values up
to J = 10)
(b) Plot 1 2 [νR(J) + νP(J +1)] against (J+1)2 and draw the best straight line through the points.
This is function f = f [(J+l)2]. Use Origin, SigmaPlot, or other statistic software to calculate a
linear regression.
(c) Compute the function f = f [(J+l)2] using Eqs. 10 and 11 to determine what the slope and
the intercept represent.
(d) Plot 1 4 [νR(J) – νP(J +1)] against (J+1) and draw the best straight line through the points. This
is function g = g[(J+1)]. Use Origin, SigmaPlot, or other statistic software to calculate a linear
regression.
(e) Do the same as in (c) for g = g[(J+l)].
(f) Calculate Ie, the moment of inertia and re, the internuclear distance. See next page for
information needed to calculate re.
(g) Tabulate the values of ν0, Be, αe , Ie , and reC H and r eCC. Compare with results from
Tidwell, etc. These are located on the last page of this manual.
(h) Compare peak intensities (absorbance values from spectra) in the C2D2 and C2H2 spectra for
even and odd J values. How does this correlate to the nuclear spin for the hydrogen and
deuterium atoms and the degeneracy for each rotational band?
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Re calculation – C2H2, C2D2
Figure 7. Moments of Inertia for C2H2.
Acetylene is a linear molecule, so Ia = 0 and Ib = Ic
To calculate re of the CH and CC bonds, the distance to the central of the molecule (rotation axis) has to be determined.
Figure 8. Drawing of C2H2 molecule with RH and RC.
The radius RH (the distance of the hydrogen atom the center of the molecule) is:
RH = 1/2 CC bond + C-H bond
The radius RC (the distance of the carbon atom the center of the molecule) is:
RC = 1/2 CC bond
Using these two radii and equation (4), you can find rCH, and rCC.
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Figure 9. Drawing of C2H2 molecule with rCC and rCH.
Inserting the radius of RH and RC into equation 4 gives:
Ie = 2 µHRH 2 + 2 µCRC
2
After performing some simple algebra, it reduces to:
Ie = 1/2 µCrCC 2 + 2 µH(rC H + 1/2rCC)2
Remember that the length for carbon-deuterium (CD) bond is the same as the length for carbon- hydrogen (CH) bond.
Discussion Questions
1. Why is the band assigned to the combination of the bending modes visible in the IR spectrum?
2. If you increase the temperature of the cell, how does the population of rotational states change?
3. At the end of the experiment, you end up with a grayish precipitate. What is this precipitate? Provide one way to completely dissolve it.
4. How can you increase the signal (or absorbance) experimentally in the IR spectrum?
Table of Molecular Constants
Isotope V0 (cm-1) Be (cm-1) B0 (cm-1) αe (cm-1) Ie (g cm2)
C2H2 1328.18 1.1751 1.1769 -0.003586 2.368×10-39
C2D2 1041.49 0.84604 0.84794 -0.003800 3.291×10-39
reCC (Å) 1.203 reCH (Å) 1.061
19
4/15/2015
References
1. Allen Jr., H. C.; Tidwell, E. D.; Plyler, E. K., J. Res. NBS 1956, 57, 213. 2. Bell, E. E.; Nielsen, H. H. J. Chem. Phys. 1950, 18, 1382. 3. Garland, C. W.; Nibler, J. W.; Shoemaker, D. P., Experiments in Physical Chemistry, 8th Ed. McGraw-Hill: New York, 2003 4. Herzberg, G., Infrared and Raman Spectra of Polyatomic Molecules, Van Nostrand Reinhold Co., New York, 1945. 5. Talley, R. M.; Nielsen, A. H. J. Chem. Phys. 1954, 22, 2030. 6. Tidwell, E. D.; Plyler, E. K., J. Opt. Soc. Am. 1962, 52 (6), 656-664. 7. Wiggins, T. A.; Plyler, E. K.; Tidwell, E. D., J. Opt. Soc. Am. 1961, 51 (11), 1219-1225.
20
,
Molecular Spectroscopy of Acetylene
Pre-Lab Questions
Please answer the following questions and attach them to your lab report before submission. These questions will account for the pre-lab and performance points and will be worth 50 points in total. Each question is worth a total of 10 points. Please limit your answer to each question to a few sentences.
1. The following energy diagram contains vibrational-rotational transitions. Answer all the questions.
a. Label all electronic, vibrational and rotational energy levels using n, V and J quantum numbers.
b. Identify P and R branches.
c. Label transitions in each of P and R branches with respect to initial and final J values.
Tips: use shapes form Insert menu for labeling
Answer:
2. The following figure shows two systems used for synthesizing C2H2 (left) and C2D2 (right). The only difference is the cold finger. Briefly explain its purpose.
Answer:
3. In the experimental demo video, the narrator mentioned a mistake that was made during filming. What was he talking about? What was the result of that mistake?
Answer:
4. The following spectra contains vibrational-rotational peaks of C2H2. Identify o and label at least 10 peaks in each of P and R branches with respect to initial J values. (Tips: use shapes form Insert menu)
5. Using slopes from the following equation and the graphs calculate , , and .
Answer:
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,
Molecular Spectroscopy
of Acetylene
Dairong Liu
SES 4340
OFFICE HOURS BY APPOINTMENT
1
Introduction
Spectroscopy is the study of
interactions between electromagnetic
radiation and matter
𝐸 = ℎ𝜈 = ℎ𝑐 ǁ𝜈 = ℎ𝑐
𝜆
Molecules get excited vibrationally by
absorbing Infrared (IR) radiations
In IR Spectroscopy molecular vibrations
are observed
IR radiation was discovered by William
Herschel in 1800
2
InfraRed Light
3
IR wavelength ranges from approx. 14000 – 40 cm-1 (between Red and Microwave)
IR activates Vibrational states
Stretching modes – NIR
Bending modes – FIR
3 types of IR:
Near IR (NIR) : 14000-4000 cm-1
Mid IR (MIR) : 4000-400 cm-1
Far IR (FIR) : 400-40 cm-1
Uses of IR Light
Science
Medicine
Industry
Telescopes
4
More Uses
Motion Sensors
Thermal Cameras
Night vision Goggles
Short range wireless communication
5
Our Application
Observe the bending mode of acetylene and its deuterium derivative
Observe rotational transitions and nuclear spin effects
Determine the rotation constant, vibration-rotation interaction constant,
moment of inertia, and bond lengths
6
Classical Mass on a Spring
Atoms bonded together act as masses on spring
Bond is not rigid
Vibration frequency depends on mass
EM absorption occurs when light frequency matches vibration frequency
Absorption causes a change in vibrational state which is detected by spectrometer
7
Hooke’s Law in Harmonic oscillator
Vibration frequency
depends on mass and
stiffness of the spring
Classical description has
continuous energy
function
Quantum energy levels
are not continuous
8
Quantum Mechanical Harmonic Oscillator
𝐸𝑣𝑖𝑏 = ℎ𝜈𝑣𝑖𝑏 = ℎ𝑐 ǁ𝜈𝑣𝑖𝑏
Energy of vibration is proportional to frequency
Absorption occurs when vibration frequency matches light frequency
Molecular vibrations have the same frequency as IR light
Quantum probability shows that vibrational energy can be outside of allowed region
9
Anharmonic Effects
Molecules cannot vibrate harmonically
Morse function describes anharmonic
oscillation
10
Conditions to Obtain IR Spectrum
Selection Rule: Dipole moment
of bond must change during
vibration
Applied frequency = Vibration
frequency
11
Rigid Rotor
For quantum number, J
We have 𝐸𝑟 = ℎ2
8𝜋2𝐼𝑒 𝐽 𝐽 + 1
If B = ℎ
8𝜋2𝐼𝑒
Then 𝐸𝑟 = 𝐵𝐽 𝐽 + 1 h 12
Rotational Spectroscopy
Molecules classified by inertial
axes
3 axes: Ia, Ib, Ic
For intertia, typically 𝐼𝑐 > 𝐼𝑏 > 𝐼𝑎
Linear Molecules: 𝐼𝑐 = 𝐼𝑏 > 𝐼𝑎
The inertia is now the sum of the
distance between each mass and
the center of mass of the rotor
multiplied by the square of the
distance between them
𝐼𝑒 = σ 𝑚𝑟2
13
a
b
c
Conditions of Rotational Spectroscopy
Selection Rules
Molecule must have a dipole moment
ΔJ = ±1
ΔMJ = 0, ±1
Spectra are symmetric
ǁ𝜈 = 𝐸
ℎ𝑐 =
ℎ
8𝜋2𝐼𝑐 𝐽 𝐽 + 1 = 𝐵𝐽(𝐽 + 1)
14
Rotational vibrational spectroscopy
15
Which one will have
higher energy?
Which EM adsorption
will have a higher
wave number?
Vibration-Rotation Coupling
Rotation happens at lower energy than
vibration
There are many rotational energy levels
between two vibrational energy levels
Rotational spectra can be obtained with IR
spectroscopy
Vibrational state dependence
𝐵𝑣 = 𝐵𝑒 − 𝛼 𝑣 + 1
2
Rotational constant, B
Vibration-Rotation interaction constant, α
16
P branch
ΔJ= -1
R branch
ΔJ= +1
Rotational-Vibrational Spectroscopy
Transitions with ΔJ = 1 are R-
branch
Transitions with ΔJ = -1 are
P-branch
𝜈𝑅 𝐽 = 𝜈𝑣𝑖𝑏 + 𝐵0 + 𝐵1 ( )
𝐽 + 1 − 𝐵0 − 𝐵1 𝐽 + 1 2
𝜈𝑃 𝐽 = 𝜈𝑣𝑖𝑏 + 𝐵0 + 𝐵1 𝐽 − 𝐵0 − 𝐵1 𝐽2
17
Fourier Transform Infrared Spectrometer
Michelson Interferometer
invented 1881
Peter Fellgett obtained first
IR spectrum with FTIR 1949
FTIR commercially available
1960
18
Fourier Transform Infrared Spectrometry
FT converts time domain to
frequency domain
Cooley-Tuckey invented algorithm
for fast FT 1966
Fast and sensitive
Scan all frequencies at once
19
Predicting the FTIR Spectrum
Number of normal modes
Non linear molecule: 3N – 6
Linear molecule: 3N – 5
Example: H2O has 3 IR modes
symmetric O-H stretching
asymmetric O-H stretching
O-H bending
3 IR bands are seen in the spectrum for water
20
Experiment Overview
Goal: Determine the bond lengths of the C-H and C≡C bonds
Simple steps:
Synthesize sample
Analyze with FTIR Spectrometer
Interpret Data
Clean Up
21
Acetylene (C2H2)
Isolate and remove IR cell for background scan (prep ice bath for reaction
flask)
Isolate manifold from reaction flask and CT
Inject Water (Deionized)
Open valve to reaction flask after 30 seconds
Isolate and remove IR cell when pressure reaches ~100 Torr for sample scan
Isolate CT from Mech Pump and open valve from manifold to CT 22
Attach reaction flask with
CaC2, IR cell, Cold Trap
(CT), and Mechanical Pump
Hose
Pump down manifold
Check for leaks
TA Add liquid N2
Di-deutero-acetylene (C2D2)
Attach reaction flask with CaC2, IR cell, Cold Finger (CF), Cold Trap, Mech pump hose
Pump down manifold
Check for leaks
T.A. add liquid N2 to CT
Isolate and remove IR cell for background scan (prep water bath for reaction flask)
Reattach IR cell and cool CF
Isolate manifold from CT
Inject D2O leaving reaction flask valves open (Pressure does not rise much)
23
Di-deutero-acetylene (C2D2) Cont.
24
After bubbling stops, isolate CT from mech pump and expose manifold to CT
Pump down manifold when pressure is stable
Isolate rxn flask when pressure is stable
Isolate manifold from CT
Remove dewar from CF
Isolate and remove IR cell for sample scan when pressure reaches ~200 Torr
Isolate CT from mech pump and expose manifold to CT
Reminders
Glass manifold – handle with care
Do not use too much CaC2
Make sure there is no water in the flask before adding CaC2
Follow manual instructions carefully
25
Clean Up
Pump down manifolds
Isolate CT from manifold and mech
pump
Remove CT and place in bucket in
fume hood
Open valve to vent CT
Leave CT in hood
Rinse CF with water in fume hood
Place CF in oven
Remove reaction flasks
Rinse with water in fume hood
Pour 1st wash in FTIR waste
Use 0.1M HCl and sonicator to
clean flasks
Pour washings down sink
Place flasks in oven
IF FLASKS CONTAIN RESIDUE FOR
THE NEXT ROTATION, POINTS WILL
BE DEDUCTED FROM REPORTS
26
Actual Spectra
27
𝜈0 = 1328.18 𝑐𝑚−1
𝑅 0 ≈ 1330 𝑐𝑚−1
𝑃 1 ≈ 1326 𝑐𝑚−1
𝜈0 = 1041.49 𝑐𝑚−1
𝑅 0 ≈ 1043 𝑐𝑚−1
𝑃 1 ≈ 1039 𝑐𝑚−1
Key point: be careful with the
wavenumbers!
Data Analysis
Identify P branch and R branch in spectrum
Label peaks with J values
Plot 1
2 [𝜈𝑅 𝐽 − 𝜈𝑃 𝐽 ] against 2𝐽 + 1
Plot 1
2 [𝜈𝑅 𝐽 − 𝜈𝑃 𝐽 + 2 ] against 2𝐽 + 3
𝐵𝑣 = 𝐵𝑒 − 𝛼𝑒(𝑣 + 1
2 )
Calculate 𝛼𝑒, 𝐵𝑒, 𝐼𝑒, 𝑟𝑒𝐶𝐶, 𝑟𝑒𝐶𝐻
Tabulate 𝜈0, 𝐵𝑒, 𝛼𝑒, 𝐼𝑒, 𝑟𝑒𝐶𝐶, 𝑟𝑒𝐶𝐻
28
Acetylene Plots
29
1
2 𝜈𝑅 𝐽 − 𝜈𝑃 𝐽 = 𝐵1(2𝐽 + 1)
1
2 𝜈𝑅 𝐽 − 𝜈𝑃 𝐽 + 2 = 𝐵0(2𝐽 + 3)
Intercept should be set to zero. It can be done in origin while taking
linear fit.
Calculations
𝐵𝑣 = 𝐵𝑒 − 𝛼𝑒 𝑣 + 1
2
𝜈𝑅 𝐽 − 𝜈𝑃 𝐽 = 2𝐵1 2𝐽 + 1
𝜈𝑅 𝐽 − 𝜈𝑃 𝐽 + 2 = 2𝐵0 2𝐽 + 3
𝐵𝑒 = ℎ
8𝜋2𝑐𝐼𝑒
𝐼𝑒 = σ 𝑚𝑅2
𝑅𝑐 = 1
2 𝑟𝐶𝐶
𝑅𝐻 = 1
2 𝑟𝐶𝐶 + 𝑟𝐶𝐻
30
Here we have 𝐼𝑒 = 2𝑚𝑅𝐶 2 + 2𝑚𝑅𝐷
2
And 𝐼𝑒 ′ = 2𝑚𝑅𝐶
2 + 2𝑚𝑅𝐻 2
Then we assume: 𝑅𝐻= 𝑅𝐷
Error Propagation
Use partial derivatives for error propagation
𝜎𝛼𝑒 2 = (
𝜕𝛼𝑒
𝜕𝐵0 )2𝜎𝐵0
2 + ( 𝜕𝛼𝑒
𝜕𝐵1 )2𝜎𝐵1
2
𝜎𝐵𝑒 2 = (
𝜕𝐵𝑒
𝜕𝐵0 )2𝜎𝐵0
2 + ( 𝜕𝐵𝑒
𝜕𝛼𝑒 )2𝜎𝛼𝑒
2 or 𝜎𝐵𝑒 2 = (
𝜕𝐵𝑒
𝜕𝐵1 )2𝜎𝐵1
2 + ( 𝜕𝐵𝑒
𝜕𝛼𝑒 )2𝜎𝛼𝑒
2
𝜎𝐼𝑒 2 = (
𝜕𝐼𝑒
𝜕𝐵𝑒 )2𝜎𝐵𝑒
2
𝜎𝑟𝐶𝐶 2 = (
𝜕𝑟𝐶𝐶
𝜕𝐼𝑒,𝐻 )2𝜎𝐼𝑒,𝐻
2 + ( 𝜕𝑟𝐶𝐶
𝜕𝐼𝑒,𝐷 )2𝜎𝐼𝑒,𝐷
2
𝜎𝑟𝐶𝐻 2 = (
𝜕𝑟𝐶𝐻
𝜕𝐼𝑒,𝐻 )2𝜎𝐼𝑒,𝐻
2 + ( 𝜕𝑟𝐶𝐻
𝜕𝐼𝑒,𝐷 )2𝜎𝐼𝑒,𝐷
2 + ( 𝜕𝑟𝐶𝐻
𝜕𝑟𝐶𝐶 )2𝜎𝑟𝐶𝐶
2
31
Lab Report – Title Page/Abstract
Title page should be simple in design
Contains experiment title centered on page in a reasonable font size
Contains author info (Name, Partner name, TA, Date) in regular font used for
report body
Abstract should be short
Short paragraph summarizing the experiment
Includes: goal of experiment, theoretical models used, results of experiment,
comparison to Tidwell et al
32
Lab Report – Data/Calculations
Data should be presented in tables with appropriate titles and significant
figures
Data in tables should include error values
Graphs should appropriately formatted with descriptive title
Graphs should be 2 or more per page (only 4 graphs in this experiment)
Graphs cannot be generated in Excel, use Origin or other software
Linear regression data must be legible
Use appropriate scientific notation when necessary (in MS Word 𝑚 × 10𝑛
should be used instead of mEn)
Use MS Word equation editor tool to show calculations
33
Lab Report – Discussion
Should explain the results of the experiments
Compare your results with Tidwell et al.
Are nuclear spin effects detected in your spectra?
Are the results expected or not?
Why did the experiment work/fail?
How does the experiment connect to the theory?
Remember sentence structure and word choice
34
Lab Report – Conclusion
Short summary of experiment
Includes obtained results, experimental success or failure
One paragraph
35
Lab Report – References
ACS style citations
Use UIC Library RefWorks if necessary
References must be cited internally and externally
Should have more references than just the lab manual
This presentation can be used as reference because it is not peer-reviewed
References can be any journal articles, textbooks, national databases
36
37
Don’t forget the
basics!
- Default Section
- Slide 1: Molecular Spectroscopy of Acetylene
- Slide 2: Introduction
- Slide 3: InfraRed Light
- Slide 4: Uses of IR Light
- Slide 5: More Uses
- Slide 6: Our Application
- Slide 7: Classical Mass on a Spring
- Slide 8: Hooke’s Law in Harmonic oscillator
- Slide 9: Quantum Mechanical Harmonic Oscillator
- Slide 10: Anharmonic Effects
- Slide 11: Conditions to Obtain IR Spectrum
- Slide 12: Rigid Rotor
- Slide 13: Rotational Spectroscopy
- Slide 14: Conditions of Rotational Spectroscopy
- Slide 15: Rotational vibrational spectroscopy
- Slide 16: Vibration-Rotation Coupling
- Slide 17: Rotational-Vibrational Spectroscopy
- Slide 18: Fourier Transform Infrared Spectrometer
- Slide 19: Fourier Transform Infrared Spectrometry
- Slide 20: Predicting the FTIR Spectrum
- Slide 21: Experiment Overview
- Slide 22: Acetylene (C2H2)
- Slide 23: Di-deutero-acetylene (C2D2)
- Slide 24: Di-deutero-acetylene (C2D2) Cont.
- Slide 25: Reminders
- Slide 26: Clean Up
- Slide 27: Actual Spectra
- Slide 28: Data Analysis
- Slide 29: Acetylene Plots
- Slide 30: Calculations
- Slide 31: Error Propagation
- Slide 32: Lab Report – Title Page/Abstract
- Slide 33: Lab Report – Data/Calculations
- Slide 34: Lab Report – Discussion
- Slide 35: Lab Report – Conclusion
- Slide 36: Lab Report – References
- Slide 37